H Algebra 2/Trig · Unit 2
The imaginary unit is i = . Rewrite square roots of negatives using i, then simplify.
The imaginary unit
i is defined as the square root of −1.
i =
That means i² = −1.
Pull out negative in radical
= i
= i = 6i
= i = 2i
Pull i out. Leave the leftover under the radical.
Pull the negative out of the radical
= i
Answer: i
Pull the negative out of the radical
= i
Answer: i
Pull the negative out of the radical
= i
Answer: i
Pull the negative out of the radical
= i
Answer: i
Pull the negative out of the radical
= i
Answer: i
Pull the negative out of the radical
= i
Answer: i
If the leftover is a perfect square, write a multiple of i. The last two have a minus in front.
Pull the negative out of the radical
= i
= 5
i · 5
5i
Answer: 5i
Pull the negative out of the radical
= i
= 3
i · 3
3i
Answer: 3i
Pull the negative out of the radical
= i
= 8
i · 8
8i
Answer: 8i
Pull the negative out of the radical
= i
= 10
i · 10
10i
Answer: 10i
Pull the negative out of the radical
− = −i
= 4
−i · 4
−4i
Answer: −4i
Pull the negative out of the radical
− = −i
Answer: −i
Pull i out, then pull a perfect square out of what is left.
Pull the negative out of the radical
= i
i = i
i · 2 ·
2i
Answer: 2i
Pull the negative out of the radical
= i
i = i
i · 5 ·
5i
Answer: 5i
Pull the negative out of the radical
− = −i
−i = −i
−i · 3 ·
−3i
Answer: −3i
Pull the negative out of the radical
2 = 2i
2i = 2i
2i · 2 ·
4i
Answer: 4i
Pull the negative out of the radical
= i
i = i
i · 3 ·
3i
Answer: 3i
Pull the negative out of the radical
−3 = −3i
−3i = −3i
−3i · 2 ·
−6i
Answer: −6i
Rewrite each square root. Combine like terms.
= 6i
3 = 3 · 3 = 9
2 = 2 · 2i = 4i
= 4
6i + 9 − 4i + 4
13 + 2i
Answer: 13 + 2i
2 = 14
= 4i
= 3i
3 = 6
14 − 4i + 3i − 6
8 − i
Answer: 8 − i
4 = 12
2 = 10i
= 6
= i
12 + 10i − 6 − i
6 + 9i
Answer: 6 + 9i
= 9i
2 = 8
5 = 10i
= 1
9i − 8 + 10i + 1
−7 + 19i
Answer: −7 + 19i
3 = 24
4 = 12i
= 6i
= 5
24 − 12i + 6i − 5
19 − 6i
Answer: 19 − 6i
= 10
= 7i
2 = 12
3 = 6i
10 + 7i − 12 − 6i
−2 + i
Answer: −2 + i
Multiply. Convert negative radicands to i first.
Pull the negative out of the radical
= i
= i
= 2
= 2i
(i)(2i)
2i² · 5
2(−1)(5)
−10
Answer: −10
Pull the negative out of the radical
= i
= 2
= 2i
= i
(2i)(i)
2i² · 2
2(−1)(2)
−4
Answer: −4
Pull the negative out of the radical
3 = 3i
2 = 2i
= 2
2 = 4i
(3i)(4i)
12i² · 3
12(−1)(3)
−36
Answer: −36
Pull the negative out of the radical
= i
= 2
= 2i
−2i · 2i
−4i²
−4(−1)
4
3i · 4
12i · 10
120i
Answer: 120i
Pull the negative out of the radical
= i
= 2
= 2i
−3i · 2i
−6i²
−6(−1)
6
= i
= 3
= 3i
−2i · 3i
−6i²
−6(−1)
6
6 · 6
36 · 5
180
Answer: 180
Pull the negative out of the radical
= i
= 2
= 2i
2i · 3i · 2i
12i³ · 15
i³ = −i
12(−i)(15)
−180i
Answer: −180i
Pull the negative out of the radical
= i
= 3
= 3i
4i · 3i
12i²
12(−1)
−12
= i
= 2
= 2i
−3i · 2i
−6i²
−6(−1)
6
(−12)(6)
−72 · 2
−144
Answer: −144
Write a squared factor twice. Rearrange with the commutative property of multiplication.
Write (5i) twice because there are two copies of 5i.
(2i)(5i)(5i)(−3i)
Use the commutative property of multiplication to rearrange the factors.
2 · 5 · 5 · (−3) · i · i · i · i
2 · 5 · 5 · (−3) = −150
i · i · i · i = i² · i² = (−1) · (−1) = 1
−150 · 1 = −150
Answer: −150
Write (3i) twice because there are two copies of 3i.
(3i)(3i)(4i)(−i)
Use the commutative property of multiplication to rearrange the factors.
3 · 3 · 4 · (−1) · i · i · i · i
3 · 3 · 4 · (−1) = −36
i · i · i · i = i² · i² = (−1) · (−1) = 1
−36 · 1 = −36
Answer: −36
Write (−2i) twice because there are two copies of −2i.
(6i)(−2i)(−2i)(i)
Use the commutative property of multiplication to rearrange the factors.
6 · (−2) · (−2) · 1 · i · i · i · i
6 · (−2) · (−2) · 1 = 24
i · i · i · i = i² · i² = (−1) · (−1) = 1
24 · 1 = 24
Answer: 24
Write (2i) twice because there are two copies of 2i.
(−4i)(3i)(2i)(2i)
Use the commutative property of multiplication to rearrange the factors.
(−4) · 3 · 2 · 2 · i · i · i · i
(−4) · 3 · 2 · 2 = −48
i · i · i · i = i² · i² = (−1) · (−1) = 1
−48 · 1 = −48
Answer: −48
Write (7i) twice because there are two copies of 7i.
(7i)(7i)(−i)(2i)
Use the commutative property of multiplication to rearrange the factors.
7 · 7 · (−1) · 2 · i · i · i · i
7 · 7 · (−1) · 2 = −98
i · i · i · i = i² · i² = (−1) · (−1) = 1
−98 · 1 = −98
Answer: −98
Write (3i) twice because there are two copies of 3i.
(−6i)(−2i)(3i)(3i)
Use the commutative property of multiplication to rearrange the factors.
(−6) · (−2) · 3 · 3 · i · i · i · i
(−6) · (−2) · 3 · 3 = 108
i · i · i · i = i² · i² = (−1) · (−1) = 1
108 · 1 = 108
Answer: 108
Need help writing numbers with i?
Book a Session with Amy